Bayes' Theorem: Disease Screening

0.0001
0.99
0.005
Posterior P(D|T) =
0.0194
0.99 × 0.0001 / (0.99 × 0.0001 + 0.005 × 0.9999)
Probability tree (per 10 000 people) 10 000 P(D)=0.0001 10 P(D^c)=0.9999 9 990 P(T|D)=0.99 ≈9.9 P(T^c|D)=0.01 ≈0.1 P(T|D^c)=0.005 ≈49.95 P(T^c|D^c)=0.995 ≈9 940 Positive tests: ≈ 9.9 + 49.95 ≈ 59.85 P(D|T) ≈ 9.9/59.85 ≈ 0.0194 ≈ 1.9% Only a small fraction of positives are true