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Atomic distributions

An atomic distribution is a probability measure that is a countable sum of point masses. It is the law of a random variable taking values in a countable set. Atomic distributions are the discrete workhorses of probability: counting, occupancy, branching, and rare-event models all live here.

Authoritative sources

Probability mass function

A distribution on a countable set SS is atomic iff there exist weights ps≥0p_s \geq 0 with ∑s∈Sps=1\sum_{s \in S} p_s = 1 such that P(X=s)=psP(X = s) = p_s for all s∈Ss \in S. The function p:S→[0,1]p: S \to [0,1] is the probability mass function (PMF).

Details

The PMF is the density of the measure w.r.t. counting measure. The CDF is a right-continuous step function: it is constant between atoms and jumps by psp_s at each atom ss. The total jump size sums to 1.

For a multivariate atomic distribution on Zd\mathbb{Z}^d, the PMF is p(x1,…,xd)=P(X1=x1,…,Xd=xd)p(x_1, \ldots, x_d) = P(X_1 = x_1, \ldots, X_d = x_d) and the joint generating function generalizes the univariate case.

Probability generating function

For XX on N0\mathbb{N}_0, the probability generating function (PGF) is

G(z)=∑k=0∞pk zk=E[zX],∣z∣≤1.G(z) = \sum_{k=0}^{\infty} p_k\, z^k = E[z^X], \quad |z| \leq 1.
Details

The PGF encodes the entire distribution: pk=G(k)(0)/k!p_k = G^{(k)}(0)/k!. It converts convolution (sum of independent variables) into multiplication, making it the natural tool for occupancy problems, branching processes, and random walks.

For a multivariate atomic distribution on N0d\mathbb{N}_0^d, the joint PGF is G(z1,…,zd)=E[z1X1⋯zdXd]G(z_1, \ldots, z_d) = E[z_1^{X_1} \cdots z_d^{X_d}].

Relationship to the MGF. For N0\mathbb{N}_0-valued variables, the PGF and the moment-generating function (see Random variables and expectation) are related by G(z)=M(log⁡z)G(z) = M(\log z) where M(t)=E[etX]M(t) = E[e^{tX}] is the MGF. The PGF is the natural tool when the support is a subset of N0\mathbb{N}_0: it always converges for ∣z∣≤1|z| \leq 1, whereas the MGF may fail to exist (e.g. for heavy-tailed discrete distributions). Reach for the PGF for counting problems; reach for the MGF when you need exponential moments or large-deviation bounds.

The relationship to Distributional structure and operations: the PGF is the generating function that makes convolution a product, which is the algebraic backbone of the convolution operation.

Common atomic distributions

DistributionPMFSupportMeanVariance
Bernoulli(p) (0/1)px(1−p)1−x{0, 1}pp(1−p)
Binomial(n, p)C(n,k) pk(1−p)n−k{0, 1, …, n}npnp(1−p)
Geometric(p) (trials to first success)p(1−p)k−1{1, 2, 3, …}1/p(1−p)/p2
Poisson(λ)λk e−λ/k!{0, 1, 2, …}λλ
Negative Binomial(r, p) (failures before r-th success)C(k+r−1, k) pr(1−p)k{0, 1, 2, …}r(1−p)/pr(1−p)/p2
Categorical(p1, …, pm)pi at category i{1, …, m}Σ i piΣ (i − μ)² pi
Details

These six families cover the vast majority of discrete models in probability and statistics. Their relationships:

The Poisson and Negative Binomial are both infinitely divisible on N0\mathbb{N}_0, but the Poisson is the canonical increment law for counting processes with stationary independent increments on a discrete time scale. See Stochastic processes for the continuous-time generalization.

Factorial moments

The factorial moment of order rr is

E[X(X−1)⋯(X−r+1)]=G(r)(1).E[X(X-1)\cdots(X-r+1)] = G^{(r)}(1).
Details

Factorial moments are the natural moments for discrete variables because they arise directly from PGF derivatives. The ordinary moment E[Xr]E[X^r] can be recovered from factorial moments via Stirling numbers of the second kind: E[Xr]=∑k=0r{rk} E[Xk‾]E[X^r] = \sum_{k=0}^{r} {r \brace k}\, E[X^{\underline{k}}] where Xk‾=X(X−1)⋯(X−k+1)X^{\underline{k}} = X(X-1)\cdots(X-k+1).

The PGF derivative formula G(r)(1)=E[Xr‾]G^{(r)}(1) = E[X^{\underline{r}}] is the discrete analogue of the MGF derivative formula M(r)(0)=E[Xr]M^{(r)}(0) = E[X^r]. Both encode all moments in a single analytic function.

Poisson limit theorem

Theorem (Poisson limit). If Xn∼Binomial(n,pn)X_n \sim \mathrm{Binomial}(n, p_n) with n pn→λn\, p_n \to \lambda as n→∞n \to \infty, then Xn→dPoisson(λ)X_n \xrightarrow{d} \mathrm{Poisson}(\lambda).

Details

The Poisson limit is the atomic analogue of the central limit theorem: it is the universal limit for rare events. The proof uses the PGF: the Binomial PGF is (1−pn+pnz)n(1 - p_n + p_n z)^n, and

(1−pn+pnz)n=(1+pn(z−1)1)n→eλ(z−1)(1 - p_n + p_n z)^n = \left(1 + \frac{p_n(z-1)}{1} \right)^n \to e^{\lambda(z-1)}

as n→∞n \to \infty with npn→λnp_n \to \lambda. Since the PGF determines the distribution, Xn→dPoisson(λ)X_n \xrightarrow{d} \mathrm{Poisson}(\lambda).

The Poisson distribution is the canonical increment law for counting processes with stationary independent increments on a discrete time scale. See Stochastic processes for the continuous-time generalization (the Poisson process).

Multivariate atomic distributions

A joint distribution on Zd\mathbb{Z}^d is atomic with PMF p(x1,…,xd)p(x_1, \ldots, x_d). Key objects:

Details

The multivariate Poisson is the canonical example of a multivariate atomic distribution with positive dependence. Its joint PGF is

G(z1,…,zd)=exp⁡ ⁣(∑i=1dλi(zi−1)+λ0(z1z2⋯zd−1)).G(z_1, \ldots, z_d) = \exp\!\Bigl(\sum_{i=1}^{d} \lambda_i (z_i - 1) + \lambda_0 (z_1 z_2 \cdots z_d - 1)\Bigr).

The λ0\lambda_0 term involves the product z1z2⋯zdz_1 z_2 \cdots z_d because N0N_0 contributes simultaneously to every XiX_i: a single event in N0N_0 increments all coordinates at once, so its generating contribution is E[z1N0⋯zdN0]=E[(z1⋯zd)N0]=eλ0(z1⋯zd−1)E[z_1^{N_0} \cdots z_d^{N_0}] = E[(z_1 \cdots z_d)^{N_0}] = e^{\lambda_0(z_1 \cdots z_d - 1)}.

Multivariate atomic distributions arise in: multinomial sampling, contingency tables, branching processes in dd types, and lattice random walks. The relationship to Absolutely continuous distributions is via the multivariate normal approximation to the multinomial (a limit theorem).

Example problem

Problem. A server receives requests according to a Poisson process with rate λ=5\lambda = 5 per minute. What is the probability that exactly 3 requests arrive in a 2-minute interval? What is the expected number of requests in that interval?

Solution

Over a 2-minute interval, the count is X∼Poisson(2λ)=Poisson(10)X \sim \mathrm{Poisson}(2\lambda) = \mathrm{Poisson}(10).

P(X=3)=103 e−103!=1000⋅e−106≈0.00757.P(X = 3) = \frac{10^3 \, e^{-10}}{3!} = \frac{1000 \cdot e^{-10}}{6} \approx 0.00757.

E[X]=10E[X] = 10.

The PGF is G(z)=e10(z−1)G(z) = e^{10(z-1)}; the factorial moment G′′′(1)=103=1000=E[X(X−1)(X−2)]G'''(1) = 10^3 = 1000 = E[X(X-1)(X-2)].