Technopedia

The technologist’s encyclopedia

Wave Propagation

Wave propagation describes how a disturbance travels through a medium or field, carrying energy without net transport of matter. It is the spatial extension of oscillation: where a single oscillator repeats in time, a wave repeats in both space and time. It is relevant to acoustics, optics, seismology, water engineering, musical instruments, and signal transmission.

Authoritative sources

The wave equation

For a 1-D string (or any linear, lossless medium):

∂2y∂t2=c2∂2y∂x2\frac{\partial^2 y}{\partial t^2} = c^2 \frac{\partial^2 y}{\partial x^2}

General solution (d’Alembert): y(x,t)=f(x−ct)+g(x+ct)y(x,t) = f(x - ct) + g(x + ct).

Details

The two terms represent waves traveling in the +x+x and −x-x directions at speed cc. For a string under tension TT with linear density μ\mu: c=T/μc = \sqrt{T/\mu}. For sound in a fluid: c=K/ρc = \sqrt{K/\rho} where KK is the bulk modulus and ρ\rho is the volume mass density. For electromagnetic waves in vacuum: c=1/μ0ε0c = 1/\sqrt{\mu_0 \varepsilon_0}.

In 3-D: ∇2y=(1/c2) ∂2y/∂t2\nabla^2 y = (1/c^2)\,\partial^2 y/\partial t^2. Spherical waves decay as 1/r1/r; plane waves do not.

Derivation from first principles

The wave equation is not an axiom; it follows directly from Newton’s second law applied to a small element of a stretched string.

Details

Consider a string of linear density μ\mu under tension TT. Take a small segment of length dxdx at position xx. The vertical forces on the segment come from the tension at each end. For small slopes ∂y/∂x≪1\partial y/\partial x \ll 1, the net vertical force is:

Fy≈T(∂y∂x∣x+dx−∂y∂x∣x)=T ∂2y∂x2 dxF_y \approx T\left(\frac{\partial y}{\partial x}\bigg|_{x+dx} - \frac{\partial y}{\partial x}\bigg|_{x}\right) = T\,\frac{\partial^2 y}{\partial x^2}\,dx

Newton’s second law for the segment (mass μ dx\mu\,dx):

μ dx  ∂2y∂t2=T ∂2y∂x2 dx\mu\,dx\;\frac{\partial^2 y}{\partial t^2} = T\,\frac{\partial^2 y}{\partial x^2}\,dx

Dividing by μ dx\mu\,dx:

∂2y∂t2=Tμ  ∂2y∂x2=c2 ∂2y∂x2\frac{\partial^2 y}{\partial t^2} = \frac{T}{\mu}\;\frac{\partial^2 y}{\partial x^2} = c^2\,\frac{\partial^2 y}{\partial x^2}

The same structure appears in every linear, lossless medium: inertia (mass per unit volume or length) on the left, a restoring mechanism (tension, bulk modulus, elastic modulus) on the right. The wave speed is always the square root of (stiffness / inertia).

Sinusoidal waves and dispersion

A monochromatic plane wave:

y(x,t)=Acos⁡(kx−ωt+ϕ)y(x,t) = A\cos(kx - \omega t + \phi)

where k=2π/λk = 2\pi/\lambda (wavenumber), ω=2πf\omega = 2\pi f (angular frequency), and c=ω/kc = \omega/k.

Details

Dispersion: In a dispersive medium, cc depends on frequency: ω=ω(k)\omega = \omega(k). The phase velocity is vp=ω/kv_p = \omega/k; the group velocity is vg=dω/dkv_g = d\omega/dk. When vg≠vpv_g \neq v_p, wave packets spread over time.

Examples:

The wave equation is universal

The same PDE ∂2y/∂t2=c2 ∇2y\partial^2 y/\partial t^2 = c^2\,\nabla^2 y appears in many physical contexts. The field variable yy and the wave speed cc change, but the mathematical structure is identical.

DomainField variable yWave speed cTypical regime
String vibrationTransverse displacement√(T/μ)1-D, non-dispersive
Acoustics (sound)Pressure deviation√(K/ρ)3-D, nearly non-dispersive
ElectromagnetismElectric / magnetic field1/√(μ₀ε₀)3-D, non-dispersive in vacuum
Deep-water gravity wavesSurface elevation√(g/k)2-D, strongly dispersive
Quantum mechanics (free particle)Wave function ψℏ/(2m) (group velocity)3-D, dispersive (Schrödinger eq.)

Recognizing this common structure lets you transfer intuition: a node in a string is the same mathematical object as a pressure node in a pipe or a field node in a cavity.

Superposition and interference

For linear media, the principle of superposition holds:

ytotal=y1+y2y_{\text{total}} = y_1 + y_2
Details

Two waves of the same frequency and amplitude traveling in opposite directions form a standing wave:

y=2Acos⁡(kx)cos⁡(ωt)y = 2A\cos(kx)\cos(\omega t)

Nodes (zero displacement for all tt) occur where cos⁡(kx)=0\cos(kx) = 0, i.e. x=(n+12)π/kx = (n+\tfrac{1}{2})\pi/k for n=0,1,2,…n = 0, 1, 2, \ldots. Antinodes (maximum displacement) occur where ∣cos⁡(kx)∣=1|\cos(kx)| = 1, i.e. x=nπ/kx = n\pi/k.

Two waves with slightly different frequencies produce beats at frequency ∣f1−f2∣|f_1 - f_2|.

Interference is the basis of diffraction gratings, noise-cancelling headphones, and the double-slit experiment.

Boundary conditions: reflection and transmission

When a wave encounters a change in medium (a junction, a fixed end, a free end), part of it is reflected and part is transmitted. The behavior is governed by the wave impedance of each medium.

Details

For a string, the wave impedance is Z=TμZ = \sqrt{T\mu} (units: N·s/m). At an interface between two strings with impedances Z1Z_1 and Z2Z_2:

r=Z1−Z2Z1+Z2,t=2 Z1Z1+Z2r = \frac{Z_1 - Z_2}{Z_1 + Z_2}, \qquad t = \frac{2\,Z_1}{Z_1 + Z_2}

where rr is the reflection coefficient (amplitude ratio of reflected to incident wave) and tt is the transmission coefficient (amplitude ratio of transmitted to incident wave).

Special cases:

The same formalism applies to:

Energy conservation requires r2+t2 Z1/Z2=1r^2 + t^2\,Z_1/Z_2 = 1 (the transmitted power is scaled by the impedance ratio).

Energy transport

The average power carried by a sinusoidal wave on a string (linear density μ\mu):

P=12 μ c ω2A2P = \tfrac{1}{2}\,\mu\,c\,\omega^2 A^2

For a 3-D medium (e.g. sound in air, volume density ρ\rho), the intensity (power per unit area) is:

I=12 ρ c ω2A2I = \tfrac{1}{2}\,\rho\,c\,\omega^2 A^2
Details

Energy is carried by the wave but the medium’s particles only oscillate locally. The energy density is split equally between kinetic and potential parts, oscillating in phase with the motion.

For sound: I=p02/(2ρc)I = p_0^2 / (2\rho c) where p0p_0 is the pressure amplitude. Here ρ\rho is the volume mass density of the medium (e.g. 1.2 kg/m³ for air), distinct from the linear density μ\mu used for a 1-D string.

The distinction: μ\mu [kg/m] is mass per unit length (1-D string); ρ\rho [kg/m³] is mass per unit volume (3-D fluid or solid). Both play the role of “inertia” in the wave speed formula.

Interactive simulation

Example problem

A string of length L=1  mL = 1\;\text{m}, linear density μ=0.01  kg/m\mu = 0.01\;\text{kg/m}, is under tension T=100  NT = 100\;\text{N}. Find the fundamental frequency of the standing wave.

Solution

Wave speed: c=T/μ=100/0.01=100  m/sc = \sqrt{T/\mu} = \sqrt{100/0.01} = 100\;\text{m/s}.

For a string fixed at both ends, the fundamental has wavelength λ1=2L=2  m\lambda_1 = 2L = 2\;\text{m}.

Fundamental frequency: f1=c/λ1=100/2=50  Hzf_1 = c/\lambda_1 = 100/2 = 50\;\text{Hz}.